Question

find the remainder when x cube + x square + X + 1 is divided by x minus 1/2 using remainder theorem

Answer 1

by remainder theorem
x minus 1/2 = 0
x = 1/2
1/2 whole cube+ 1/2 whole square + 1/2 + 1
= 15/8
hope that this helps u

Answer 2

Answer:

$\text{The remainder is }\frac{15}{8}$

Step-by-step explanation:

we have to find the remainder when the polynomial $x^3+x^2+x+1$ is divided by $x-\frac{1}{2}$ using remainder theorem.

$p(x)=x^3+x^2+x+1$

$\text{Put }x=\frac{1}{2}$

By remainder theorem

$p(\frac{1}{2})=(\frac{1}{2})^3+(\frac{1}{2})^2+(\frac{1}{2})+1$

            $=\frac{1}{8}+\frac{1}{4}+\frac{1}{2}+1$

            $=\frac{15}{8}=\frac{15}{8}$

$\text{The remainder is }\frac{15}{8}$