plz ans 8 ques 8 i.e. in triangle ABC ..........
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to prove angle a =90°
ad^2 =bd*cd. ( given)
ad*ad= bd*cd.
ad/bd. = cd/ad. ............... (1)
in ∆abd and cad
ad=ad. (common)
ad/bd=. cd/ad. ......... given
by sss criteria. ∆abd and cad are congruent.
then angle. DBA=DAC. = 0°
and. angle dab. =DCA=90-0°
now. angle. A. = DAC + BAD
=thus angle A= 90-0°+0°
= 90 °.
hence proved
that ∆abc is a right angled triangle at. A.
ad^2 =bd*cd. ( given)
ad*ad= bd*cd.
ad/bd. = cd/ad. ............... (1)
in ∆abd and cad
ad=ad. (common)
ad/bd=. cd/ad. ......... given
by sss criteria. ∆abd and cad are congruent.
then angle. DBA=DAC. = 0°
and. angle dab. =DCA=90-0°
now. angle. A. = DAC + BAD
=thus angle A= 90-0°+0°
= 90 °.
hence proved
that ∆abc is a right angled triangle at. A.
sakshi2608:
or why
I don't know sorry
angle dba =dac. by ( cpct ) as we proved. triangle abd and cad are congruent
oh thank you
it's your welcome
and sorry i forgot to write cpct in answer
ok
and yes it is not 0°. it is thetha. as we supposed
ok
thank u
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