Find the remainder when x2013 is divided by (x+1)³
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Answer:
USING LONG DIVISION METHOD
(x+1)³ = x³+1+3x²+3x
= x³+3x²+3x+1
divided by x,
x) x³+3x²+3x+1 ( x²+3x+3
x³
------------------
3x²+3x+1
3x²
------------------
3x+1
3x
-----------------
1
remainder is 1
OR
USING REMAINDER THEORM
p(x) = (x+1)³
g(x) = x
equate x to 0
x = 0
substitute in p(x)
(0+1)³ = (1)³ = 1
remainder = 1
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