Find the remainder when x3+3x2+1 is divided by 2x+5
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Answer:
x^3+3x^2+1÷2x+5
2x+5=0
2x=-5
x=-5/2
p(x)=x^3+3x^2+1
p(-5/2)=(-5/2)^3+3(-5/2)^2+1
= -125/8+3(25/4)+1
= -125/8+75/4+1
=33/8
Therefore, 33/8 is the remainder.
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