find the remainder when x3+ 3x2+3x. + 1 by x+ π
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Answer:
hey mate
g(x) x+π= 0
x = -π
p(x) = x³+ 3x² + 3x +1
put the x= -π in p(x)
= (-π)³ + 3×-π + 3×-π +1
= π³ -3π² -3π +1
hope it will help you
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