Math, asked by jinny4850, 1 year ago

find the remainder when x³+3x²+3x+1 is divided by x+1​

Answers

Answered by arpi1401
16

Answer:

hence, the remainder will be zero...

Attachments:
Answered by Anonymous
20

Answer:

0.

Step-by-step explanation:

Given :

\large \text{$p(x)=x^3+3x^2+3x+1$ and $g(x)=x+1$}

Zeroes of g ( x ) = x  + 1 = 0

x = - 1

Now putting x = - 1 in p ( x ) we get

\large \text{$p(x)=x^3+3x^2+3x+1$}\\\\\\\large \text{$p(-1)=(-1)^3+3(-1)^2+3(-1)+1$}\\\\\\\large \text{$p(-1)=-1+3-3+1$}\\\\\\\large \text{$p(-1)=0$}

So remainser is 0.

Also know :

If we put g ( x) value and remainder comes zero then g ( x ) is a

factor of polynomial x.

Similar questions