Find the remainder when x3 - 3x2 + 3x - 1 is divided by x−12
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Divisor: x – 12 [Let it be = g(x)]
Dividend: x³ – 3x² + 3x – 1 [Let it be = p(x)]
Zero of g(x):-
x – 12 = 0
⟹ x = 12
Putting the value of 'x' in p(x):-
p(x) = x³ – 3x² + 3x – 1
∴ p(12) = (12)³ – 3(12)² + 3(12) – 1
= 1728 – 3(144) + 36 – 1
= 1728 – 432 + 36 – 1
= 1331 [Remainder]
@Psyclone
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