Question

find the remainder when x³–3x²+3x-1 is divided by x+3​

Answer 1

Answer:

x= -3

p (-3)=(-3)^3-3 (-3)^2+3 (-3)-1

= -27-27-9-1

= -64

the remainder is -64

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Answer 2

p of x = x+3=0

= x=0-3

therefore x= -3

p of x=(-3)^3-3(-3)^2+3(-3)-1

p of x=(-27)-3(9)-9-1

p of x=(-27)-27-11

p of x=(-54)-11

p of x=(-65)

that's solve

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