find the remainder when x³+3x²+3x+1 is divided by x
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6
Answer:
By remainder theorem
x+1=0
x=−1
p(x)=x
3
+3x
2
−3x−1p(−1)
=(−1)
3
+3(−1)
2
−3(−1)−1
=−1+3(1)+3−1
=−1+3+3−1
=6−2
=4
Thus remainder is 4
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