Find the remainder when x³+3x²+5x+6 divisible by 2x+4 and specify is it factor of taht polynomial ?
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Step-by-step explanation:
p(x)=x3−3x2+5x+7
Remainder =p(3)=(3)3−3(3)2+5(3)+7=27−27+15+7=22
For (x−3) to be a factor, p(3) must be equal to zero.
Here, p(2)=0.
Hence, (x−3) is not a factor of this polynomial.
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Here's the answer mate.
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