Question

find the remainder when x3 -ax2+3x-2a is divide by x-a



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Answer 1

Answer:

By remainder theorem

x+1=0

x=-1

p(x) = {x}^{3} + {3x}^{2} - 3x - 1p(x)=x

3

+3x

2

−3x−1

p( - 1) = {( - 1)}^{3} + 3 {( - 1)}^{2} - 3( - 1) - 1p(−1)=(−1)

3

+3(−1)

2

−3(−1)−1

= - 1 + 3(1) + 3 - 1=−1+3(1)+3−1

= - 1 + 3 + 3 - 1=−1+3+3−1

\begin{gathered} = 6 - 2 \\ \\ = 4\end{gathered}

=6−2

=4

Thus remainder is 4

Step-by-step explanation:

hope it helpful

Answer 2

Answer:

remainder is -a

quotient is x^2+3