find the remainder when x3 -ax2+3x-2a is divide by x-a
Answers
Answered by
1
Answer:
By remainder theorem
x+1=0
x=-1
p(x) = {x}^{3} + {3x}^{2} - 3x - 1p(x)=x
3
+3x
2
−3x−1
p( - 1) = {( - 1)}^{3} + 3 {( - 1)}^{2} - 3( - 1) - 1p(−1)=(−1)
3
+3(−1)
2
−3(−1)−1
= - 1 + 3(1) + 3 - 1=−1+3(1)+3−1
= - 1 + 3 + 3 - 1=−1+3+3−1
\begin{gathered} = 6 - 2 \\ \\ = 4\end{gathered}
=6−2
=4
Thus remainder is 4
Step-by-step explanation:
hope it helpful
Answered by
0
Answer:
remainder is -a
quotient is x^2+3
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