find the remainder when x³-ax²+ ax²+ 6x-a / x -a
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4
x-a = 0
x= a
So, a^3-a(a^2)+6a-a
a^3-a^3+5a
0+5a
5a
The remainder is 5a
x= a
So, a^3-a(a^2)+6a-a
a^3-a^3+5a
0+5a
5a
The remainder is 5a
Answered by
5
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