find the remainder when x3 (x to the power 3) + 6x2 (x to the power 2) + 1 3x +60 is divided by x+2
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put x=-2 in the equation
then,
(-2)^3+6×(-2)^2+13(-2)+60
-8+24-26+60
=50
then,
(-2)^3+6×(-2)^2+13(-2)+60
-8+24-26+60
=50
anu161:
I didn't understand teh sum
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