Question

find the remainder when xcube+3xsquare+3x+1 is divided by rhe linear polynomials by x​

Answer 1

Answer:

By remainder theorem

x+1=0

x=−1

p(x)=x  

3

+3x  

2

−3x−1p(−1)

=(−1)  

3

+3(−1)  

2

−3(−1)−1

=−1+3(1)+3−1

=−1+3+3−1

=6−2

=4

Thus remainder is 4

Step-by-step explanation:

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