Find the reminder when
p(x)=x^3+3x^2+3x+1 is divided by x+1
Answers
Answered by
1
Answer:
By remainder theorem = p( -1 )
p( x ) = x^3 + 3x^2+3x +1
p ( -1 ) = (-1)^3 + 3( -2)^2 +3(-1)+1
= -1 +12 - 3 + 1
= 9
Therefore the remainder is 9
Hope it will help you......
Mark as brainlist plz.....☺️☺️☺️
Have a nice day
and
Always keep smiling
Answered by
1
Answer:
Here is the answer with correct explanation
Attachments:
Similar questions