find the reminder when
plzzzzzzz solve quickly first answer will be marked as brainlist
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⭐hey there!!
=> given eqn is : let f(x) = x² - ax²+ 6x - a is divided by (x-a)
So by remainder theorem,
=> x-a = 0 then x = a
Put x = a in above equation. We get
=> f(a) = a² - a.a² + 6.a - a
=> f(a) = a² - a³ + 6a - a
=> f(a) = a² - a³ + 5a
So required remainder is ( a²- a³ + 5a)
_______________________________________
⭐hope it will help u
=> given eqn is : let f(x) = x² - ax²+ 6x - a is divided by (x-a)
So by remainder theorem,
=> x-a = 0 then x = a
Put x = a in above equation. We get
=> f(a) = a² - a.a² + 6.a - a
=> f(a) = a² - a³ + 6a - a
=> f(a) = a² - a³ + 5a
So required remainder is ( a²- a³ + 5a)
_______________________________________
⭐hope it will help u
aarvikhan2:
kyaa
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0
hope this helps you.
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