Question

find the reminder when x^3 + 3x^2 + 3x +1 divided by :: x+π (pie)


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Answer 1

$p(x) = {x}^{3} + 3 {x}^{2} + 3x + 1$

$= > x + \pi = 0$

$= > x = - \pi$

Now,by using the remainder theorem-------

$p(</strong><strong>-</strong><strong>\</strong><strong>pi) = { - \pi}^{3} + 3( { - \pi})^{2} + 3 ({ - \pi}) + 1$

$= > - {\pi}^{3} + 3 {\pi}^{2} - 3\pi + 1$

Thus,the remainder is----

${ - \pi}^{3} + 3 {\pi}^{2} - 3\pi + 1$