Question

Find the resistance across the wire. Please give the solution along with the process.​

Answer 1

Answer:

Explanatio find equivalet resistance 1st in close loop then in series accross AB.

Answer 2

$\huge\underline\green{\sf Answer:-}$

★$\large{\boxed{\sf R_{eq}=6 ohm}}$

$\huge\underline\green{\sf Solution:-}$

★In first step :-

Both side are in series so :-

For series combination :-

$\large{\sf {R}=R_{1}+R_{2}}$

$\large\implies{\sf 2+2}$

$\large\implies{\sf 4 ohm}$

Similarly for the other side too.

★In second step :-

Both the 4 ohm Resistance are parallel to eachother :-

For parallel combination :-

$\large{\sf {\frac{1}{R}}={\frac{1}{R_{1}}}+{\frac{1}{R_{2}}}}$

$\large\implies{\sf {\frac{1}{4}}+{\frac{1}{4}}}$

$\large\implies{\sf 2 ohm}$

★In third step :-

All the three resistance are in series so ,

$\large{\sf R_{eq}=2+2+2}$

★$\huge\red{\boxed{\sf R_{eq}=6 ohm}}$