Find the resistance drawn from the battery by the network of 4 resistors shown in the figure.
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There are two sets of resistances connected in parallel which themselves have two 10 ohm resistances connected in series.
so the equivalent resistance of each series connected sets become (10+10) ohm = 20 ohm
Now,
The two sets connected in parallel together give an equivalent resistance of 20*20/20+20 ohm's = 10 ohms
So ,
Current = Potential difference/Resistance = 3/10 Amperes = 0.3 Amperes.
so the equivalent resistance of each series connected sets become (10+10) ohm = 20 ohm
Now,
The two sets connected in parallel together give an equivalent resistance of 20*20/20+20 ohm's = 10 ohms
So ,
Current = Potential difference/Resistance = 3/10 Amperes = 0.3 Amperes.
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