find the resistance in the following figure
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I got answer 8/15 ohm. sorry if I made any mistakes
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Answer: →R₁ and R₂ are in series:
R₅ = 2 + 2
R₅ = 4 omh
→R₃ and R₄ are in series:
R₆ = 4 + 4
R₆ = 8 omh
→ R₅, R₆ and R₇ are in parallel, (Let Rₙ be equavelent Resistance)
1/Rₙ = 1/R₅ + 1/R₆ + 1/R₇
1/Rₙ = 1/4 + 1/8 + 1/5
1/Rₙ = 23/40
Rₙ = 40/23 omh
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