Find the resistance of a conductor through which 2.4 x 10 ki power 20 elections flow in 80 seconds on the supply of na voll potential difference?
Answers
it is given that 2.4 × 10^20 electrons flow through a conductor in 80 seconds on the supply of 10 volts potential difference.
we have to find the resistance of the conductor
net charge = no of electrons × charge on each electron
= 2.4 × 10^20 × 1.6 × 10^-19
= 2.4 × 1.6 × 10
= 2.4 × 16
= 38.4 Coulombs
current = charge/time
= 38.4/80
= 0.48 A
using Ohm's law R = V/I = 10/(0.48) = 20.83 Ω
hence, resistance of the conductor is 20.83 Ω
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Answer:
net charge = no of electrons × charge on each electron
= 2.4 × 10^20 × 1.6 × 10^-19
= 2.4 × 1.6 × 10
= 2.4 × 16
= 38.4 Coulombs
current = charge/time
= 38.4/80
= 0.48 A
using Ohm's law R = V/I = 10/(0.48) = 20.83 Ω