Physics, asked by bhavyadaga0502, 11 months ago

Find the resistance of a conductor through which 2.4 x 10 ki power 20 elections flow in 80 seconds on the supply of na voll potential difference?

Answers

Answered by abhi178
0

it is given that 2.4 × 10^20 electrons flow through a conductor in 80 seconds on the supply of 10 volts potential difference.

we have to find the resistance of the conductor

net charge = no of electrons × charge on each electron

= 2.4 × 10^20 × 1.6 × 10^-19

= 2.4 × 1.6 × 10

= 2.4 × 16

= 38.4 Coulombs

current = charge/time

= 38.4/80

= 0.48 A

using Ohm's law R = V/I = 10/(0.48) = 20.83 Ω

hence, resistance of the conductor is 20.83 Ω

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Answered by Anonymous
0

Answer:

net charge = no of electrons × charge on each electron

= 2.4 × 10^20 × 1.6 × 10^-19

= 2.4 × 1.6 × 10

= 2.4 × 16

= 38.4 Coulombs

current = charge/time

= 38.4/80

= 0.48 A

using Ohm's law R = V/I = 10/(0.48) = 20.83 Ω

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