Question

find the resistance of an electric bulb of 0.06A current is passing through it and the potential difference across the bulb is 90V​

Answer 1

Answer:-

• Current=I=0.06A
• Potential Difference=V=90V
• Resistance=R=?

According to ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \rm\longmapsto Resistance=\dfrac{90}{0.06}$

$\\ \rm\longmapsto Resistance=1500\Omega$