Physics, asked by jibyaj912, 11 months ago

Find the resistance of eureka wire 1.1m long and 0.2mm in diameter. Resistivity of eureka=49 X 10-8 ῼm​

Answers

Answered by jeehelper
0

The resistance will be 17.16 ohm

Explanation:

Diameter of eureka = d = 0.2 mm

Area of eureka = A =π(d/2)^2 = π(0.2m/2)^2 = 3.14 × 10-8 m^2

Length of eureka = l = 1.1m

Specific resistance of eureka = ρ = 49 X 10-8 ohm.m

Now we know that:

R = ρ l/A

By putting values in equation (i) we get,

R = 17.16 ohm

Which is the required resistance.

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