Find the resistances of two resistors connected in parallel where, One resistor is three times as large as the other. The total resistance is 12 ohms.
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1/3x + 1/x = 1/12
=> (1+3)/3x =1/12
=> 4/12x =1/12
=> x = 4
Resistances are 4 ohm and 12 ohm
=> (1+3)/3x =1/12
=> 4/12x =1/12
=> x = 4
Resistances are 4 ohm and 12 ohm
sophiajara15:
wouldn't that be wrong. the total resistance is 12 ohms
Answered by
1
Hey friend
let the larger resistor be x and small resistor be 3x
R equivalent in parallel combination
=>r eq.=1/r¹+1/r²
Now
=> 12=1/3x+1/x
=>12=4/3x
=>36x=4
=>x=9
So large resistor =9ohm
small resistor= 3ohm
let the larger resistor be x and small resistor be 3x
R equivalent in parallel combination
=>r eq.=1/r¹+1/r²
Now
=> 12=1/3x+1/x
=>12=4/3x
=>36x=4
=>x=9
So large resistor =9ohm
small resistor= 3ohm
the formula is 1/r = 1/r1 + 1/r2
since it is parallel connection
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