find the resistors in parallel combination . 2ohm,8ohm,6ohm
Answers
Answered by
1
Explanation:
1/R=1/2+1/8+1/6
=12+3+4/24
=19/24
R=24/19ohm
Answered by
1
Answer:
24 / 19 ≈ 1.26 Ω
Explanation:
Let say :
R₁ = 2 Ω
R₂ = 8 Ω
R₃ = 6 Ω
We're asked to find net resistance when all connected in parallel :
We know :
1 / R_net = 1 / R₁ + 1 / R₂ + 1 / R₃
Putting values here we get :
1 / R_net = 1 / 2 + 1 / 8 + 1 / 6
= > 1 / R_net = ( 12 + 3 + 4 ) / 24
= > 1 / R_net = 19 / 24
= > R_net = 24 / 19 ≈ 1.26 Ω
Hence we get required answer
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