Physics, asked by kunal228damahe, 10 months ago

i) A particle performs linear S.H.M.

starting from the mean position. Its

amplitude is A and time period is T. At

the instance when its speed is half the

maximum speed, its displacement x is

(A) 3

2

A (B)

2

3

A

(C) A

2 (D) 1

2

A

ii) A body of mass 1 kg is performing linear

S.H.M. Its displacement x (cm) at t

(second) is given by

x = 6 sin (100t + π/4). Maximum kinetic

energy of the body is

(A) 36 J (B) 9 J

(C) 27 J (D) 18 J

iii) The length of second's pendulum on the

surface of earth is nearly 1 m. Its length

on the surface of moon should be [Given:

acceleration due to gravity (g) on moon

is 1/6 th of that on the earth’s surface]

(A) 1/6 m (B) 6 m

(C) 1/36 m (D) 1

6

m

iv) Two identical springs of constant k are

connected, first in series and then in

parallel. A metal block of mass m is

suspended from their combination. The

ratio of their frequencies of vertical

oscillations will be in a ratio

(A) 1:4 (B) 1:2 (C) 2:1 (D) 4:1

v) The graph shows variation of

displacement of a particle performing

S.H.M. with time t. Which of the

following statements is correct from the

graph?

(A) The acceleration is maximum at

time T.

(B) The force is maximum at time 3T/4.

(C) The velocity is zero at time T/2.

(D) The kinetic energy is equal to total

energy at time T/4.​

Answers

Answered by Anonymous
0

Answer:

 \sec( \sec( \sec( log_{ \sec( \gamma  \sec(?) ) }(?) ) ) )

Answered by arunimabanerjee17
0

Answer:

I don't know and answers sorry I cannot give your answers if I will give I will give long answer for this so please don't ask me I have not heard this question only anywhere please ask someone else about this question I think there anyone is can help you in this question sorry again I cannot help you I think you can understand

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