Question

Find the result of mixing 10 gram of ice at -10 degree Celsius with 10 gram of water at 10

degree Celsius. Specific heat capacity of ice = 2.1 j/ g /K , specific latent heat of ice = 336

joule per gram and specific heat capacity of water = 4.2 joule per gram per Kelvin.​

Answer 1

Answer:

Your search - Find the result of mixing 10 gram of ice at -10 degree Celsius with 10 gram of water at 10 degree Celsius. Specific heat capacity of ice = 2.1 j/ g /K , specific latent heat of ice = 336 joule per gram and specific heat capacity of water = 4.2 joule per gram per Kelvin. - did not match any image results.

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