Question

Find the resultant moment of couple if two equal forces each of 6N are acting at a distance of 3cm each from the centre.​

Answer 1

Answer:

The answer is described as given below

Explanation:

Given: F

1

=F

2

=5N,d

1

=d

2

=0.5m

Torque τ=F×d

tau

1

=F

1

×d

1

=5N×0.5 m

=2.5 Nm (Anti-clockwise)

τ

2

=F

2

×d

2

=5N×0.5 m

=2.5 Nm (Anti-clockwise)

The resultant moment of force =τ

1

+τ

2

=2.5+2.5=5 Nm in Anti clockwise direction.