Question

.. Find the resultant of the following two vectors A and B.
A: 40 units due east and ; B:25 units 37° north of west
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Answer 1

Answer:

Explanation:

=> First of all, break the second vector into NSEW components. The  

north component is 25*sin(37)=25*0.60 = 15 and the west component is 25*cos(37) = 25*0.80 = 20.

=> The resultant vector is 5 units to the west and 15 units to the north.

40 units due east - 1 vector  

25 units at an angle of 143 with 1 vector measured anticlockwise - 2 vector  

=> now use the formula sqrt(40^2+25^2+2*40*25*cos(143)) = 25 ( after simplification)  

=> The angle of this vector from the west direction is arctan(15/5) = 72°.  

=> thus, 25 units 72° north of west