Chemistry, asked by 162665, 1 month ago

find the resultant of two forces, one 3N due north and 4N due east?​

Answers

Answered by Kaushalsingh74883508
0

Explanation:

X = 4N.

Y = 3N.

X + Yi + F3 = 0

4 + 3i + F3 = 0

F3 = -4 - 3i

Tan Ar = Y/X = -3/-4 = 0.75000

r = 36.87o(Q1). = Reference angle.

A = 36.87 + 180 = 216.87o(Q3).

F3 = X/Cos A = -4/Cos216.87 = 5.0 N. @

216.87o.

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