Question

find the resultant of two forces p= 200kN &
8 = 150 KN angle between the milis 45°
calculate the resultant force & direction of
resellent
force​

Answer 1

Answer:

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Answer 2

If R is the resultant force between two forces $F_{1}$ and $F_{2}$ acting at an angle of α wrt each other, then by the cosine rule of resolution of vector forces we have,

R² = $F_{1}$² + $F_{2}$² + 2$F_{1}$$F_{2}$ cosα

and

tan β = $\frac{F_{2} sin\alpha }{F_{1} + F_{2}cos\alpha }$

Given that,

$F_{1}$ = 200 kN

$F_{2}$ = 150 kN

α = 45°

∴ Using cosine rule formula,

R² = 200² + 150² + 2.200.150.cos45

∴ R² = 104926.406 kN

∴ R = 323.92 kN

and

tanβ = $\frac{150*sin45}{200+150cos45}$

∴ tanβ = 0.3465

∴ β = 19.11° from the 200 kN force.