find the resultant resistance in this type of connection(the connection is provided in the image)
the question supports 4 options as well those are -
A) 4 ohm
B) 6 ohm
C) 8 ohm
D) 12 ohm
answer all the questions correctly the best answer will be marked as brainliest answer plzz answer with explanation
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The answer is B) 6 ohm
explanation:-
first of all take the resistors which are connected in parallel. the formula for resistance in parallel
1/Rp = 1/R1 + 1/R2
putting values in above formula
1/Rp = 1/4 + 1/4
= 1+1/4 (by taking LCM)
=2/4
1/Rp = 1/2
Taking Reciprocals
Rp = 2
Now take in series
to calculate resistance in series tge dormula is
Rs = R1 + R2
Rs = 4 + 2
Rs= 6
therefore the answer is 6 ohms
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explanation:-
first of all take the resistors which are connected in parallel. the formula for resistance in parallel
1/Rp = 1/R1 + 1/R2
putting values in above formula
1/Rp = 1/4 + 1/4
= 1+1/4 (by taking LCM)
=2/4
1/Rp = 1/2
Taking Reciprocals
Rp = 2
Now take in series
to calculate resistance in series tge dormula is
Rs = R1 + R2
Rs = 4 + 2
Rs= 6
therefore the answer is 6 ohms
Please mark as a Brainlist
XD
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