Question

find
the roof of
of the equache

${x}^{2 } + 7x + 10 = 0$
​

Answer 1

roots are -5 and -2

Step-by-step explanation:

x² + 7x +10 = 0

x² +5x +2x +10 = 0

x(x+5)+2(x+5) = 0

(x+2)(x+5) = 0

so, x+2 = 0

x = -2

or

x+5 = 0

x = -5

pls mark as brainliest

Answer 2

Answer:

Answer=>roots=-5 and -2.

Step-by-step explanation:

x^2+7x+10=0

x^2+2x+5x+10=0

x(x+2)+5(x+2)=0

(x+5)(x+2)=0

(x+5)=0 or (x+2)=0

x=-5 or x=-2

Hope this helps you.