Question

find the roors of a quadratic equation X^2+√2X-12

Answer 1

Answer:

Step-by-step explanation:

x^2 +2x-12=0

b^2-4ac=(root2)^2-(4×1×-12)

= 2+48

=50

x=(-b+_root(b^2-4ac))/2 a

=(-root 2 +_root 50)/2

so,

(1), x=(-root2+root50)/2

and

2

(2), x=(-root2-root 50)/2