find the root for 2xx-x+1/8=0
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Hi Buddy!
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Look its simple :
2x²-x+1/8=0
MBS by 8
16x² -8x + 1= 0
16x² - 4x - 4x + 1 = 0
4x(4x -1) -1(4x-1) = 0
(4x-1) (4x-1) = 0
either (4x-1) = 0 or (4x-1) = 0
ultimately x = +1/4 and +1/4
____________________________________________________________
Look its simple :
2x²-x+1/8=0
MBS by 8
16x² -8x + 1= 0
16x² - 4x - 4x + 1 = 0
4x(4x -1) -1(4x-1) = 0
(4x-1) (4x-1) = 0
either (4x-1) = 0 or (4x-1) = 0
ultimately x = +1/4 and +1/4
atchu3737:
what is MBS?
Megabits per second, Mb/s,
thanq
can you mark me as branilliest
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