Question

Find the root of 3x² - 4√3x + 4 = 0.

Answer 1

Hola RehanA

3x² - 4√3 + 4 = 0

Here , a = 3 , b = -4√3 , c = 4

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x = \frac{4 \sqrt{3} + - \sqrt{48 - 48} }{6} \\ \\ x = \frac{4 \sqrt{3} }{6} \\ \\ x = \frac{2 \sqrt{3} }{3} \\ \\ x = \frac{2}{ \sqrt{3} }$

Hope it helps

Answer 2

i think d answer is right!