Question

find the root of following quadratic equation by the method of completing the square
1.2x^2-7x+3=0​

Answer 1

$2{x}^{2} - 7x + 3 = 0 \\ 2 {x}^{2} - (6 + 1)x + 3 = 0 \\ 2 {x}^{2} - 6x - x + 3 = 0 \\ 2x( x - 3) - 1(x - 3) = 0 \\ (x - 3)(2x - 1) = 0 \\ so \: x = 3 \: \: and \: x = \frac{1}{2}$

Hope it helps....

♥️#thank you#♥️

Answer 2

$\huge\boxed{\boxed{\fcolorbox{white}{pink}{Answer}}}$

❥ $2{x}^{2} -7x+3=0$

❥ $2{x}^{2}-(6+1)x+3=0$

❥ $2{x}^{2} -6x-1x+3=0$

❥ $2x(x-3)-1(x-3) =0$

❥ $(2x-1)(x-3)=0$

❥ $x = 3, \large{\frac{1}{2}}$

Hope it helps úh