Question

find the root of given quadratic equation: x^2+x-365=0​

Answer 1

Answer:

${x}^{2} + x - 365 = 0$

$d = {b}^{2} - 4ac \\ d = {1}^{2} - 4 \times 1 \times ( - 365) \\ = 1 + 1460 \\ = 1461$

Answer 2

Step-by-step explanation:

Answer:

\begin{gathered}{x}^{2} + x - 365 = 0 \\\end{gathered}

x

2

+x−365=0

\begin{gathered}d = {b}^{2} - 4ac \\ d = {1}^{2} - 4 \times 1 \times ( - 365) \\ = 1 + 1460 \\ = 1461\end{gathered}

d=b

2

−4ac

d=1

2

−4×1×(−365)

=1+1460

=1461