Question

if tan thita =1 then ,find the values of sin thita + cos thita / sec thita + cosec thita​

Answer 1

Answer:

$tanx = 1 \\ it \: means \: x = 45 \: degrees \\ \frac{sinx \: + cosx}{secx + cosecx} \\ = \frac{sinx \: + cosx}{ \frac{1}{cosx} + \frac{1}{sinx} } \\ = \frac{sinx \: + cosx}{ \frac{sinx \: + cosx}{sinx \: cosx} } \\ sinx \: cosx \\ = sin45 \times cos45 \\ = \frac{1}{ \sqrt{2} } \times \frac{1}{ \sqrt{2} } = \frac{1}{2}$

Answer 2

Answer:

nhi pata

Step-by-step explanation:

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