Question

find the root of quadratic equation 3xsq.-5x+2=0

Answer 1

Hey friend, Harish here.

Here is your answer.

Given Quadratic Equation :

3x² - 5x + 2 = 0

To Find :

The roots of the above quadratic equation

Solution :

3x² - 5x + 2 = 0

⇒ 3x² - 3x - 2x + 2 = 0

⇒ 3x (x - 1) -2 (x-1) = 0

⇒ (3x - 2) (x-1) = 0

Now we can note the , this is only possible only in two cases.

Case 1 :

(3x - 2) = 0

Then , x = 2/3

Case 2 :

(x - 1) = 0

Then, x = 1

∴ The roots of the quadratic equation are 2/3 and 1.

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Hope my answer is helpful to you.

Answer 2

$\red{Hello \: Friends\: }$

$\bold{Given \: quadratic \: equation}$

$\bold{3x {}^{2} - 5x + 2} = 0$

$\underline{Roots \: of \: the \: given \: quadratic \: equation}$

BY SPITING THE MIDDLE TERM,,,,

$\bold{ = > 3x {}^{2} - 5x + 2 = 0} \\ \\ \bold{ = > 3x {}^{2} - 3x - 2x + 2 = 0 } \\ \\ \bold{ = > 3x(x - 1) - 2(x - 1) = 0} \\ \\ \bold{ = > (x - 1) \: \: (3x - 2) = 0}$

$\red{when....}$


$\bold{(x - 1) = 0} \\ \\ \boxed{x = 1}$

$\green{when....}$

$\bold{(3x - 2) = 0} \\ \\ \bold{3x = 2} \\ \\ \boxed{x = \frac{2}{3} }$

$\boxed{Ans \: = > \: x = 1 \: or \: x = \frac{2}{3 \: } \: are \: the \: roots}$

$\blue{Thanks \: for \: the \: question \: }$

$\boxed{ \: Be \: Brainly}$