Question

find the root of quadratic equation by using the quadratic formula of each 2 x square - 3 x minus 5 equals to zero​

Answer 1

Answer:

-1 and 5/2

Step-by-step explanation:

Given a quadratic equation such that

$2 {x}^{2} - 3x - 5 = 0$

To find the zeroes of the equation.

We need to factorise the given equation.

We will use middle term splitting method for this process.

In this method, we have to split the middle term into two terms such that their product will be equal to the product of the first and last terms.

Therefore, we will get,

$= > 2 {x}^{2} + 2x - 5x - 5 = 0 \\ \\ = > 2x(x + 1) - 5(x + 1) = 0 \\ \\ = > (x + 1)(2x - 5) = 0$

Now, we have two cases.

When x + 1 = 0

=> x = -1

When 2x - 5 = 0

=> 2x = 5

=> x = 5/2

Hence, the zereos are -1 and 5/2.

Answer 2

2x square - 3x - 5 =0

2x square -5x +2x - 5 =0

2x (x + 1) - 5( x +1 )

x = -1 or x = 5/2