Question

Find the root of quadratic equations x2-2x-8_0

Answer 1

EXPLANATION.

Roots of the quadratic equation.

⇒ x² - 2x - 8 = 0.

As we know that,

Factorizes the equation into middle term splits, we get.

⇒ x² - 4x + 2x - 8 = 0.

⇒ x(x - 4) + 2(x - 4) = 0.

⇒ (x + 2)(x - 4) = 0.

⇒ x = - 2   and   x = 4.

                                                                                                                     

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.

Answer 2

Answer:

Given :-

• The equation,
• ${x}^{2} - 2x - 8 = 0$

○To find :-

• The roots.

○Solution :-

• Now factorusing the equation we get,
• ${x}^{2} - 4x + 2x - 8 = 0$
• $x(x - 4) + 2(x - 4) = (x - 4)(x + 2)$
• $x = - 2 \: \: \: or \: x = 4$

○Therefore ,

• The roots are -2 and 4.

○Used formula :-

• Factorisation method.

□Hope it helps u mate .

□Thank you .