find the root of the equation 16×x-10÷x=27
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16x-10×1/x=27
16x^2-27x-10=0
by solvingnthe equation two roots obtain one is 4 and other is -10/32
16x^2-27x-10=0
by solvingnthe equation two roots obtain one is 4 and other is -10/32
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