find the root of the equation
16X-10/x=27
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16x-10/x=27
16x2-10÷x=27
16x2-10=27x
16x2-27x-10 =0
16x2-(32-5)x-10=0
16x2-32x-5x-10=0
16x (x-2)+5(x-2)=0
(16x+5)(x-2)=0
16x+5=0
16x=-5
x=-5/16
x-2=0
x=2
(-5/16,2)
I think this is right
please mark as brainliest
16x2-10÷x=27
16x2-10=27x
16x2-27x-10 =0
16x2-(32-5)x-10=0
16x2-32x-5x-10=0
16x (x-2)+5(x-2)=0
(16x+5)(x-2)=0
16x+5=0
16x=-5
x=-5/16
x-2=0
x=2
(-5/16,2)
I think this is right
please mark as brainliest
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