Question

Find the root of the equation 16x - 10/x= 27
(class 10 CBSE SAMPLE PAPER 2017-18 MATHS)

Answer 1

SOLUTION:


16x - 10/x= 27


(16x(x) - 10)/x = 27


16x² -10= 27x


16x²-27x-10=0


16x²-32x +5x-10=0


[By middle term splitting]


16x(x-2)+5(x-2)=0


(16x+5) (x-2)=0


16x+5=0  or  x-2=0


16x=-5 , x=-5/16;      x=2


Hence, the two roots of the equation are x= -5/16 & x=2.


HOPE THIS WILL HELP YOU….

Answer 2

heya,☺

it's too easy

16x-10/x=27

=)16x^2-10/x=27

=)16x^2-10=27x

=)16x^2-27x-10=0

=)16x^2-32x+5x-10=0

=)16(x-2)+5x(x-2)=0

=)(5x+16)(x-2)=0

=)so,1st root be,2 .

and second root be, -16/5=-3.2.

hope it help you brainly helper.

@rajukumar☺