Question

find the root of the equation 5=2/3(2x-1)

Answer 1

The answer to your question is in the picture.

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Answer 2

HEY MATE,
HERE IS YOUR ANSWER,


=​3​​2​​(2x−1)

1

 

Simplify \frac{2}{3}(2x-1)​3​​2​​(2x−1) to \frac{2(2x-1)}{3}​3​​2(2x−1)​​

5=\frac{2(2x-1)}{3}5=​3​​2(2x−1)​​


2

 

Multiply both sides by 33

5\times 3=2(2x-1)5×3=2(2x−1)


3

 

Simplify 5\times 35×3 to 1515

15=2(2x-1)15=2(2x−1)


4

 

Divide both sides by 22

\frac{15}{2}=2x-1​2​​15​​=2x−1


5

 

Add 11 to both sides

\frac{15}{2}+1=2x​2​​15​​+1=2x


6

 

Simplify \frac{15}{2}+1​2​​15​​+1 to \frac{17}{2}​2​​17​​

\frac{17}{2}=2x​2​​17​​=2x


7

 

Divide both sides by 22

\frac{\frac{17}{2}}{2}=x​2​​​2​​17​​​​=x


8

 

Simplify \frac{\frac{17}{2}}{2}​2​​​2​​17​​​​ to \frac{17}{2\times 2}​2×2​​17​​

\frac{17}{2\times 2}=x​2×2​​17​​=x


9

 

Simplify 2\times 22×2 to 44

\frac{17}{4}=x​4​​17​​=x


10

 

Switch sides

x=\frac{17}{4}x=​4​​17​​






Decimal Form: 4.25