Question

Find the root of the equation 5x²-6x-2=0​

Answer 1

Answer:

5x²-6x-2=0

Step-by-step explanation:

5x²-6x-2=0 ...(i)

Compare equation (i) ax^2 + bx +c = 0

a = 5,  b= -6, c= -2

$b^2-4ac$ = 36-4(5)(-2) = 36 +40 = 76

x=$\frac{-b ± \sqrt{b^2-4ac} }{2a}$ = $\frac{-(-6) ± \sqrt{76} }{2(5)}$

     $x=\frac{6 ± \sqrt{4* 19} }{10}=\frac{6 ± 2\sqrt{ 19} }{10}\\x= \frac{3 ± \sqrt{ 19} }{5}\\\\x=\frac{3 + \sqrt{ 19} }{5}\ or\ x= \frac{3 - \sqrt{ 19} }{5}$

are the roots of the given equation.

Note; A is not the part of equation it was added as I used(±) so don't write A

       Sorry for the inconvenience.