Math, asked by drsagar648, 1 year ago

Find the root of the following x square - 6x - (a square + 2a-8 )=0

Answers

Answered by MMaina
0

Answer:

x = -(a+4) Or x = (a-2)

Step-by-step explanation:

Given quadratic equation:

x²+6x-(a²+2a-8)=0

=> x²+6x-(a²+4a-2a-8)=0

=> x²+6x-[a(a+4)-2(a+4)]=0

=> x²+6x-(a+4)(a-2)=0

Splitting the middle term,we get

=>x²+(a+4)x-(a-2)x-(a+4)(a-2)=0

=> x[x+(a+4)]-(a-2)[x+(a+4)]=0

=> [x+(a+4)][x-(a-2)]=0

=> x+(a+4)=0 Or x-(a-2)=0

=> x = -(a+4) Or x = (a-2)

Therefore,

x = -(a+4) Or x = (a-2)

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