Find the root of the quadratic equation a2x2-3abx+2b2=0
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Answered by
212
Hi ,
a² x² -3abx + 2b² = 0
a² x² - abx - 2abx + 2b² = 0
ax( ax - b ) - 2b( ax - b ) = 0
( ax - b )( ax -2b ) = 0
Therefore ,
( ax -b ) = 0 or ax -2b = 0
ax = b or ax = 2b
x = b / a or x = 2b / a
I hope this helps you.
:)
a² x² -3abx + 2b² = 0
a² x² - abx - 2abx + 2b² = 0
ax( ax - b ) - 2b( ax - b ) = 0
( ax - b )( ax -2b ) = 0
Therefore ,
( ax -b ) = 0 or ax -2b = 0
ax = b or ax = 2b
x = b / a or x = 2b / a
I hope this helps you.
:)
Answered by
42
Answer:
here is your answer guys
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