Question

find the root of the quadratic equation by using
thr forumula
$2 {x}^{2} - 7x + 3$
​

Answer 1

Step-by-step explanation:

ᴘɪᴄ ʀᴇғᴇʀs ᴛᴏ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ...

Answer 2

$\star\:\:\:\bf\large\underline\blue{Question:-}$

• Find the roots of the Quadratic equation by formula.

$\star\:\:\:\bf\large\underline\blue{Solution:-}$

$2 {x}^{2} - 7x + 3 = 0$

Here,

$a = 2$

$b = - 7$

$c = 3$

So,

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

$= \frac{7 \pm \sqrt{49 - 24} }{4}$

$= \frac{7 \pm5 }{4}$

So,

$x_{1} = \frac{7 + 5}{4}$

$= 3$

$x_{2} = \frac{7 - 5}{4}$

$= \frac{1}{2}$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• The roots of the quadratic equation are 3 and 1/2.